c - Printf ubuntu Segmentation fault (core dumped)


I have this code:

int a;
printf("&a = %u\n",(unsigned)&a);

I tried to print the pointer of a variable.
But it fail on the row printf("a\n"); and says Segmentation fault (core dumped)

&a = 134525024
Segmentation fault (core dumped)

When I remove the row printf("&a = %u\n",(unsigned)&a); from the code, its success. Output:


What worng in my code?

2 Answers: 

This could be an architecture problem. I ran this on OS X and it ran fine:

#import <stdio.h>
int main()
    int a;
    printf("&a = %u\n",(unsigned int)&a);

However, I did get a warning during compilation:

warning: cast from pointer to integer of different size

I am on a 64-bit machine, so my 64-bit pointers can't fit into a 32-bit int. Try running this instead and see what you get:

#import <stdio.h>
int main()
    int a;
    printf("unsigned %ld\n", sizeof(unsigned)); // sizes reported in bytes
    printf("int %ld\n", sizeof(int));           // same as unsigned
    printf("long %ld\n", sizeof(long));         // should fit a pointer
    printf("ptr %ld\n", sizeof(void*));         // size of a pointer
    printf("&a = %lu\n", (unsigned long)&a);    // should print out your pointer
    printf("&a = %p\n", &a);                    // the Right Way of doing things


unsigned 4
int 4
long 8
ptr 8
&a = 140734544742408
&a = 0x7fff508c0808


Just in case you didn't know, unsigned actually means unsigned int. Likewise, long actually means long int.

Also, whether a value is signed or unsigned does not change its physical size, only how it is interpreted. You can see that from the first 2 prints.


I solvd my problem. I just reinstall my ubuntu and the vmware, now its work. I am not realy sure what the exact problem, but it solved my problem... :-)


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